Stata remove from string. strtrim(“ nyush ”) = “nyush” .

Stata remove from string There was a related issue/question posted earlier today: http://www. h" #include <iostream> #include <str The Stata date function is smart about removing separator characters. This probably answers the question, but the problem is very poorly described. However, when I do that, STATA creates a number which ignores all the values following comma. 1 I have a string variable and some of the responses have an extra character at the beginning. It might be helpful to > mention that > simbols are actually numbers. In Stata 13 and later versions, this can be done in one line using the built-in command rename. The char() function should allow you to specify these characters, but whether they will The four functions trim the strings by removing the spaces. From: Michael McCulloch <[email protected]> Re: st: editing string variables to remove letters and keep only numbers. After a bit more exploration I found the solution: foreach i of varlist _all { local a : variable label `i' local a: subinstr local a "’" "'" label var `i' "`a'" } On Fri, Apr 9, 2010 at 11:49 AM, Anna Reimondos <[email protected]> wrote: > Hello, > I am currently cleaning a dataset but am having some trouble with the > variable labels. Removes all leading and trailing white-space characters from the current String object. Is there a way in Stata to remove the excess D character? My data looks like this Well, if you do not know, wether all letters capitalized, this modification may workout for you, it is basically adding the upper() function: replace postcode Check for that . > If the characters are Dear all, I would like to destring string variable, which contains comma as a decimal separator . katrina wilson. ) > replace oldstring = subinstr(oldstring, "-", "",. And your output will be "123data-". Use list to list data when you are doing so. Hello Stata nerds, does anyone know how to remove ALL special characters from a string variable without also removing spaces? 12:25 AM · Sep 21, 2019. @jww: I assume you're talking about the last code sample and n is the original string length. 2, -dataex- is already part of your official Stata In this case I can remove > spaces using: > replace brand=trim(brand) > > The problem is that Stata reads some spaces as “?”. Another solution would make use of the more recently added function strrpos() gen Wanted2 = substr(Var, 1, strrpos(Var, "|")) which will delete everything from the start of the string through the first right bracket and the space that follows the bracket. Trim(); If this isn't working then it highly likely that the "spaces" aren't spaces but some other non printing or white space character, possibly tabs. replace the commas between fields with spaces, leaving commas within fields untouched. ) I am trying to remove a specific pattern of numbers from a string using the regexr function in Stata. I am Login or Register Log in with Forums FAQ Search in titles only Search in In this case I can remove >> spaces using: >> replace brand=trim(brand) >> >> The problem is that Stata reads some spaces as “?”. However, here is a sequential strategy. For each input character, I do 1 character test O(1), and 0 or 1 character append. harvard. The second two commands deal with HHID by forcing Stata to interpret it as a number. erase(std::remove(s. The first column shows the code you would use, the second column shows how your data might look like before applying the code, and the third column shows how your data would look like after applying the code. Removing 0s from string 21 Nov 2022, 13:59. The character in question is a constant character in all cases. And How can you delete observations from a variable that contains strings that have the specific word for instance. Hot Network Questions Is Instant Reload the only way to avoid provoking an attack of opportunity while reloading a projectile weapon? Applying for B1B2 US visa while I’m in Canada Could space tourism ever offer total solar eclipse viewings by traveling near the tip of the Moon's umbra as it's projected String. So, to be fully general, we need the code to remove " DEAD" when it appears at the end of the string, and, I presume, if a string contains DEAD both at the end and somewhere else, it should remove only the one at the end. This syntax extracts the substring starting from the first character to the second to last character of the string, which Notice: On April 23, 2014, Statalist moved from an email list to a forum, based at statalist. Replace instances of "," with " " i. In this post –which will be continuously updated– we present random string functions that we think are extremely useful for Stata users. I am looking to find an efficient way to remove spaces while renaming a string variable. For example, instead of G23 I have DG23. 1, an easy way to see all the special characters and their ASCII codes is the -asciiplot- command, authored by Michael Blasnik, Svend Juul, and Nick Cox, and available on SSC. ", "",. ) Joseph's advice is spot on. org. It is probably simplest for you to repeat import excel or import delimited and flag that the first row of the data file is to be treated as indicating variable names. I want to remove any pattern of numbers that are not bounded by a character (other than whitesp Skip to main content. ) which I think would work if I had only numerical/string values, but with a combination of both I'm for sure confusing the system. From: Nick Cox <[email protected]> Prev by Date: Re: st: finicky graph parsing; Next by Date: RE: st: finicky graph parsing; Previous by thread: st: RE: remove special characters from string As an aside, for those using Stata versions 8. What I would like to do, is to take the first part of the string before the -symbol. ) should do it. Below is a basic example of how to hide the time from a date when displaying the data. > > As a beginner to Stata, I was wondering if anybody could The ASCII code for CR (carriage return) is 13 and for LF (line feed) is 10. 2 through 13. However, the order of the variables is not strings first, >> numeric second. Thus said, I created a minimal data example for you and wrote a short while-loop I have a string variable in Stata which includes the company names. Then same advice as above. More strange thing is that on screen of data editor, Stata shows “?” like the following, but if I double click, neither a space or “?” is not there. My variables look like this: var1 is labeled: Thank you for your submission to r/stata! If you are asking for help, please remember to read and follow the stickied thread at the top on how to best ask for it. However, the order of the variables is not strings first, > numeric Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand The char() function calls up particular ASCII characters. Please does anyone know how I can remove the special characters and after that split the Stata remove entire word from string. Suppose you haven't spotted that a few observations don't follow this pattern. I want to remove all such characters from the end of the company name. Here string stands for any string containing characters other than Re: st: Re: Removing commas & periods from numbers. generate v2 = date(v1, "YMD") format %td v2 The YMD is called a mask, and it tells Stata the order in which the parts of the date are specified. From: Nick Cox <n. Follow answered Mar 23, 2022 at 18:49. Blake Heller. Converting an Excel file into a dta. S. Without using the "subinstr" command How not completely clear to me; however, if there are no commas in the country name ever, then I think you are better using strrpos to get the position the last comma and taking everything after that as the country; help for strrpos can be found in help for string functions (sorry, but the forum software does not like this function name and keeps changing it on me - I hope it Stata Help < [email protected] > Subject Re: st: Generating a new var from last 11 character in a string: > Dear listers > > I want to do generate a new var from the last 11 character of a string variable. The first column shows the code you would use, the second column shows how your data might look like before applying the code, and theafter replace tags = subinstr(tags, `"""', "", . Quote. > I tried to (Not sure why!) > Thus, Stata formats some variables as string and some as numeric > during the import (using the import "text data from a spreadsheat" > menu). ) a string with the first characters of Unicode words titlecased and other characters lowercased ustrto(s,enc,mode) converts the Unicode string s in UTF-8 encoding to a string in encoding enc ustrtohex(s,n) escaped hex digit string of sup to 200 Unicode characters ustrtoname(s,p) string stranslated into a Stata name Look at each character in turn and decide whether it is a letter; or a number or decimal point; or something else (implicitly) and build up answers that way. function calls up particular ASCII characters. com/support/faqs/data-management/counting-distinct-strings/index. ac. In this case I can remove spaces using: replace brand=trim(brand) The problem is that Stata reads some spaces as “?”. In this case, trim > does not work. You want the syntax to work on the name of the variable, which has to be different. ASCII 160 is an example. list, clean noobs add1 add2 132f larchmont road 132 f larchmont road flat 1a 1 bramley road flat 1 a 1 bramley road flat 1a 7 woodland avenue flat 1 a 7 woodland avenue flat 1a copthall house gloucester crescent flat 1 a copthall house gloucester crescent flat 1a hood court north street Clear All. See help string functions in Stata 14 for documentation of strrpos(). I am trying to come up with a way to remove consecutive spaces from a string. Look for " aka " as a substring. For example (here using bars as the forum does not allow more than one space): How can I remove an accent mark,or another characters such as (/;,:) from a string variable? 23 May 2016, 17:27 I have a string variable with a lot of characters that are not alphabet letter. But Stata returns “observation contains nonnumeric characters; no replace” (string(my_variable)) list my_variable if non_numeric. Hi Stata users, I am using European data, and it has punctuation for thousand separator, and comma for decimal separator. (There is a section on removing non-numeric text from numeric data. In Stata you would call this changing the format. " <[email protected]> st: RE: Line break in a character string for a bar chart label. Step 3. ) How can I destring it correctly? The easiest way to remove the last character from a string in SAS is to use the SUBSTR function. It's not clear to me quite what you are asking. This CSV file contains list of all those ID's whose documents Stata remove entire word from string. From: Skipper Seabold <[email protected]> st: RE: remove special characters from string. Like so: Orginal Variable CC547A1 | VC549F| PC5297 New Variable 18547A1 | 75549F | 355297 they are built in to Stata; trim() is the old name, strltrim() is the current name (as of version 14 IIRC); type "h function" and click on "string functions" and scroll down Nick [email protected] Oleksandr Shepotylo > I need to remove blanks in strings of the folloving structure: > "xxxxxxxxx x", where x is a simbol. In this case, trim >> does not work. The logic is this. I would like to remove the first two numbers after the : so that it . So, this may not be your best strategy. It might be helpful to mention I now realized that if we want STATA to deal with time we have to convert the string variable representing date into "STATA internal form" (count of seconds, days, months or years from 1960) first and then if necessary, change read into Stata as string variables because they contain spaces, dollar signs, commas, and percent signs. Create a variable which is only a certain portion of a string variable in Stata. Post Cancel. Also, Stata would extract from the value in the first observation only. Characters before/after a symbol. Comment. Try out the last word as a daily date. uk> Prev by Date: st: RE: handling the quote character stored in a string variable; Next by Date: Re: st: handling the quote character stored in a string variable; Previous by thread: st: RE: handling the quote character stored in a string variable Follow-Ups: . Separate numbers and words in a string. It's all hodgepodge. For example, I have a variable of jobtitle and the observations can vary "CEO" "Chief Executive Officer" "President" "President & CEO" "President & Chief Executive I have a column "v3" where there are numbers with "â¯" inside them e. st: Replace string characters disregarding the position of the character in the string. set obs 1 Number of observations (_N) was 0, now 1. So I have since tried gen year= (substr(string(fiscal_year_ended),-4,. The first two commands eliminate any leading or trailing blanks, and reduce any sequences of internal blanks to a single blank. >> >> I want to remove all the stray single quote marks. njcoxstata@gmail. you might have problems removing the "â " and "¯" characters since they are extended ASCII characters. Remove trailing punctuation from concatenated string. I would like it to be 12345678. 1 Setting Up. To be clear on terminology here, a string may contain zeros in leading positions, such as "0string"; in trailing positions, such as "string00"; in both; or in some intermediate position, such as "string000string". ) I think you want Hi I would use "destring" with the " force" option (which would return you a variable with only the numeric IDs). replace('data-',''); will only replace the first matching text. From Amanda Fu < [email protected] > To [email protected] Subject Re: st:how to delete anything in the bracket for a string variable: Date Sun, 9 Oct 2011 09:24:29 -0400 In addition to Eric's helpful and detailed suggestions, check out http://www. html Nick [email I'm trying to use reshape with a string variable, but my string variable contains special characters. If that works remove it. replace add1 = ustrregexra(add1, "([0-9]) ([a-z]) +", "$1$2 ") (5 real changes made) . 7â¯455 and i want it to be just 7455 I was trying replace v3 = "" if v3 == "â¯". This is good, but not I would say optimal. I normally count the possitions that i want and use the substring command, but my oldvar has contains different number of characters. e. Removing characters before a certain value in variable names in stata. About; Products Stata remove entire word from string. st: editing string variables to remove letters and keep only numbers How to remove contents of string after a character. ) replace oldstring = subinstr(oldstring, "-", "",. Character append is O(1) is enough memory is reserved, or O(current_length) if a new buffer is allocated. but it does since it is within a number it does not identify it. How do you that? With a string function. How can you delete observations from a variable that contains strings that have the specific word for instance. Join Date: Apr 2021; Posts: 11 #1 gen year=substr(fiscal_year_ended,-4,. Now the discussion has moved onto upper/lower case letters, I feel I should point out that my suggestion below strips off anything that is not a digit between 0 and 9 - this may or may not be beneficial depending on the situation, but in the case of valid postcodes it should be irrelevant! Dear Stata users, I am trying to separate addresses inside a string variable into new observations, like: from: "address11 // address12 // address13" clear input str42 var1 "address11 ///// address12 / address13" "address21 ///// address22 /// address23" "address31 // address32 // address33" end *Remove the / characters replace var1 References: . For example, if a variable contains " Arizona", a command that contains an if command such as if state="Arizona" won’t detect this observation. The subinstr() solution in the OP's answer works only if the text to remove occurs just once as an entire variable name, and does not occur as part of another variable name. Stata - Extract numbers before characters, create a list. 3. Martin Weiss " Does not -subinstr- work for string observation, and not variable names?" -subinstr (Not sure why!) >> Thus, Stata formats some variables as string and some as numeric >> during the import (using the import "text data from a spreadsheat" >> menu). For example, I might want > to remove all punctuation so > hi. You can use the following basic syntax to do so: data "statalist hsphsun2. If you do output. Cambridge, MA 01238-1234" "12345 Main St Sommerville MA 01239-2345" "12345 Main St is legal and returns a substring of the data whenever the argument is the name of the string variable. Join Date: Feb 2020; Posts: 181 #1 How to replace comma(,) with punctuation(. Suppose I have a CSV file that contains a variable called ID (string) and is unique on it. becomes hithereguys > > I'd love to Suppose you wish to remove leading or trailing zeros from a string variable (or from a global or local macro). From: Nick Cox <[email protected]> Re: st: Removing quotation marks in string variables. Ylenia Curci So my recommendation is: Go back to the original parser, clean up, and then import into Stata. I am trying to create a do file to import a bunch of these files into Stata and need a reliable method to remove the www. How to extract components of a disorganized string variable in Stata? 1. I am trying to remove special characters from the variable below: dataex issue_type "إثبات ملكية_x000d_منع معارضة واثبات ملكية_x000d_" "منع معارضة واثبات ملكية_x000d_" "تقسيم الأموال المشتركة المنقولة وغير المنقولة - إزالة الشيوع_x000d_" Remarks and examples stata. We will show some examples of how to use regular expression to extract and/or replace a portion of a string variable using these three <> In addition, look at -charlist- from SSC to look at these characters. The codes contain 6 digits each, but some of them have two 0s as the first two digits (ex. 584 2 2 gold badges 7 7 silver badges 27 27 bronze badges. st global("r(N)", "") would delete r(N) whether it were a macro, scalar, or matrix. Next by thread: RE: st: RE: trimming leading numbers from a string. strtrim(“ nyush ”) = “nyush” Note that real()/string() are functions and must be used in conjunction with a Stata command. ) for the decimal separator 12 Oct 2020, 14:00. ) However, nothing happened. > I tried to do it in Excel that is supposed to be very > simple, but it > deletes zeroes in the beginning or end of the strings I have a basic question, which I still have not been able to solve. st: Line break in a character string for a bar chart label. Improve this answer. Step 2. not "aka". From: "Radwin, David" <[email protected]> Re: st: RE: Line break in a character string for a bar chart label Using Stata to delete files from folders 26 Oct 2020, 11:04. If you find it, remove it and what follows. Post Stata estimation routines automatically drop observations with missing values on any of the variables - beginners often think they need to drop observations with missing data before a There is a specific function in Stata 14+ to look for the last occurrence of a substring (e. This is documented: Splitting a string variable in Stata, and placing values in order. From: "Data Analytics Corp. Post Cancel The dataset attached is malformed for Stata purposes as metadata appear in the first observation and as a side-effect all variables are string. From: Michael McCulloch <[email protected]> References: . 001005). Yes, I do want the stubs for reshape long and additional steps that run summary statistics later (hence the preference for globals). replace('data-','');, as mentioned, but as replace() only replaces the FIRST instance of the matching text, if your string was something like "data-123data-" then "data-123data-". Thus the result of removing pig from this list with equivalent but not identical syntax is Dear all, I would like to destring string variable, which contains comma as a decimal separator . end(), '\t'), s. Ed Suh. From: Nick Cox <[email protected]> Re: st: editing string variables to remove letters and keep only numbers. Extracting text from a string before the first occurrence of st: RE: handling the quote character stored in a string variable. Is there a way (ideally without using mata) to do something like Prev by Date: st: Removing quotation marks in string variables; Next by Date: Re: st: Removing quotation marks in string variables; Previous by thread: st: Removing quotation marks in string variables; Next by thread: Re: st: Removing quotation Stringfunctions 5 uchar(𝑛)Description: theUnicodecharactercorrespondingtoUnicodecodepoint𝑛oranemptystringif 𝑛isbeyondtheUnicodecode-pointrange This page shows examples of how one might use string related commands in STATA. stata: remove everything after the last occurrence of a specified character. (In your case the data wouldn't be legal as variable names. stata. Usage: txt = txt. you can try using the 3rd party "charlist" command (written by Stata guru Nick Cox) to get a list of the ASCII values of the characters in the string, and then use the char() function nested within a subinstr() function to delete instances of extended ASCII values. If you drop an observation you drop all the values it contains on all variables. From: "Ben Carpenter" <[email protected]> Prev by Date: st: Replace string characters disregarding the position of the character in the string; Next by Date: Re: st: Forest plot of hazard ratios For example, 1:2013-cv-10153 and 0:1979-cv-06704. DEMO. To find what you can do type in Stata help datetime_display_formats. remove(hello, "o"); Share. Probably, the spaces are meaningless. I want to remove words, if and only if replace my_string_variable = subinstr(my_string_variable, " ", "", . Find the dash. More strange thing is that on screen of data editor, >> Stata Hello the Statalist Community, I have a string variables which contains spaces in some of the values as Prefixes and suffixes as shown below string_var" Kenya" Joseph's advice is spot on. I've formatted it so that it no longer appears in scientific notation in the data editor, but when I do "tab variable", it truncates yet again to scientific notation and collapses together different values (i. For example, I need to change all instances of CC to 18, VC to 75, and PC to 35. For more information on Statalist, see the FAQ. . From: Raphael Fraser <[email protected]> Prev by Date: Re: st: Validation Sample Stats; Next by Date: Re: st: displaying summation of a variable; Previous by thread: st: Removing commas & periods The context is that you want to remove variable names from a string listing them. clear input id str40 string 1 "9884 7-test 58 - 489" 2 "67-tty 783 444" 3 "j3782 3hty" end gen N_words Clear All. However, when I do that, STATA creates a number which st: editing string variables to remove letters and keep only numbers. Splitting string data and This does not "remove the prefix/suffix", but does instead remove as many characters, which only matters if it's not certain that the string actually starts/ends with the pre-/suffix but is an important caveat about this solution to keep in mind. Using Stata 12, I want to replace some substrings in a string variable. Thank you, Nick. I just want to flag that leading and trailing spaces is also common jargon here. Here string stands for any string containing characters other than String hello = "hellO world"; String hellYeah = StringUtils. They won't remove either certain ASCII characters that look like spaces. Stack Overflow. Use the advanced editing options to appropriately format quotes, data, code and Stata output. There are some very good summaries that cover aspects of string variables (e. — Obtain strings from and put strings into global macros Stata component/action function call r() results macro obtain contents contents = st global("r(name)") removes a value label association from variable whatever without destroying the value labels. exactly!" 3. We will show some This page shows examples of how one might use string related commands in STATA. So if you want all matches of text to be replaced in string you have New to locals and for loops but I basically want to remove string characters from labels in a loop, so that I can make multiple graphs. Regression in Stata by industry: How to get categories in a variable as the title for the resulting regression output? Hot Network I'm trying to remove a specific word from a certain string using the function replace() or replaceAll() but these remove all the occurrences of this word even if it's part of another word! Example: String content = "is not like is, but mistakes are common"; content = content. string() string(n) is a synonym for strofreal(n) and converts numeric or missing values to strings. ) rename `var' `newname' } Nick [email protected] > -----Original Message----- > From: [email Try format %20. Tom Carmi Tom Carmi. or You should give specific details. com Stata understands stritrim(), strltrim(), strrtrim(), and strtrim(), as synonyms for its own itrim(), ltrim(), rtrim(), and trim() functions, so you can use the str*() names in both your Stata and Mata code. Describe your dataset. You could then remove those IDS from your string vars (using if conditions) , perform your routine (below) then bring back the non When dealing with string variables in Stata, blanks spaces can make it difficult to identify values. Hot Network Questions Returning a sequence from a function Implied warranties vs. Conformability stritrim(s), strltrim(s), strrtrim(s), strtrim(s): s: r c result: r c Diagnostics None. To trim blank spaces (ASCII space character char(32)) at the beginning or the end of the value, Stata has different built-in strip x, of(". . OP: there's a fundamental difference between "values" and "variables". For example “AMC Concord”, “amc concord” and “AMC CONCORD If you want to remove all occurences in the string, then you can use the erase/remove idiom: #include <algorithm> s. N. com/statalist A port of first call here for such problems is the help for string functions. 2. (stata) file Refer to iteration number inside for-loop in Stata. How to split a string variable and add its values in separate rows. gen newvar = "output" if strmatch(reg_id, "input*") is in fact the simplest way to get what you ask. There are other variables in the data set that will get picked up by p_*_0 that I don't want in this stub list. 4. Many company names have phrases such as "INC" or "CO" or " & CO" in the end of their name. - then replace oldstring = subinstr(oldstring, ". If your dates are in v1 and in the form yyyy-mm-dd you can specify the commands:. That requires a few little tricks: if substr(name, See the -help- on -functions-, particularly string function. Use input to type in your own dataset fragment that others can experiment with. foreach var of varlist data* { local newname = substr("`var'", 5, . Hello everyone, I'm currently working with a dataset which uses a code to identify specific companies. How do you find the right one? Read help string functions. See help datetime_translation under the section "the date function". > The above code will strip out everything except alphanumeric characters from dirty_string to create clean_string. Dear All, This may come as an odd request however, I am trying to understand whether the following can be addressed using Stata. new posts. Forums for Discussing Stata; General; You are not logged in. Hence If I have a string Suppose you wish to remove leading or trailing zeros from a string variable (or from a global or local macro). I want to remove from my variable time the part 30dec1899. 16 or a fully updated version 15. "Say exactly what you typed and exactly what Stata typed (or did) in response. From: Raphael Fraser <[email protected]> References: st: Removing commas & periods from numbers. You can browse but not post. Note that although we loop over the length of the string, looping over observations too is tacit. j. I apologize for the difficult presentation and thanks for generating the sample data. com string — String manipulation functions ContentsDescriptionRemarks and examplesAlso see Contents [M-5] Manual entry Function Purpose Parsing tokens() tokens() obtain tokens (words) from string invtokens() invtokens() concatenate string vector into string scalar strmatch() strmatch() pattern matching tokenget()::: advanced parsing Length & position Nick [email protected] Martin Weiss Sent: 29 June 2010 12:23 To: [email protected] Subject: AW: st: Remove numbers from variable name <> But careful! A "two-digit- question" would comply with the if-branch in Nick`s solution as well. Re: st: editing string variables to remove letters and keep only numbers. end()); If you want to remove only the tab at the beginning and end of the string, you could use the boost string algorithms: You can use "data-123". st: RE: Removing trailing letter from string From: "Nick Cox" <[email protected]> Prev by Date: st: RE: Removing trailing letter from string Next by Date: st: RE: RE: RE: Removing trailing letter from string Previous by thread: st: RE Nick [email protected] Oleksandr Shepotylo > I need to remove blanks in strings of the folloving structure: > "xxxxxxxxx x", where x is a simbol. The how could I delete the observations that contain the letters "ur", in this case "saturn" and "uranus" ? Most often when I search the internet for help on Stata, it is probably when I need to work with string variables (such as names). ) the " you will lose that. Re: st: RE: trimming leading numbers from a string. Words in Stata are just whatever spaces separate (modulo binding in double quotation or compound double quotation marks). Thanks Nick, but doesn't it imply that the blanks are actually blanks and not any other string characters? But anyway, I was able to solve the issue by using replace var1=substr(var1,5,. String processing is fairly easy in Stata because of the many built-in string functions. e. 10f The "12" in front of the decimal is the total number of digits, including decimal point, I believe, that Stata allocates to the variable. there,gu;ys. , this page). The solution above has been possible since early versions of Stata (with the proviso that strpos() was earlier known as index()). If so, you will have messed up your data. com . Please also note our request that members use full real names. , anything that would be scientifically noted as 1. I have already tried: replace x = subinstr(x," ", "", . Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Yes, I had to ultimately give up after spending hours thinking about the anomalous (buggy) nature of -ltrim- (even -charlist- did not pick out a non-blank character Stata remove entire word from string. ) That’s different from text files, like CSVs, that can contain both text and numeric data. ,;") g(new_x) li T On Wed, Nov 23, 2011 at 2:57 PM, Cory Smith <[email protected]> wrote: > Hiya all, > I'm looking to use regular expressions or another command to remove an > arbitrary list of characters from a string. > replace oldstring = subinstr(oldstring, ". cox@durham. In this case, trim does not work. Retweet. edu" < [email protected] > Subject st: remove blanks in a string: Date Thu, 8 Apr 2004 11:00:03 -0400: Dear statalist, Probably very simple question, but I could not find simple solution: I need to remove blanks in strings of the folloving structure: "xxxxxxxxx x", where x is a simbol. 1 like Comment Hello; I have a lengthy (10 to 12-digit) numeric identifier in my data. 6. We saw how to do this using the Data Editor in [GSW] 6 Using the Data Editor; this chapter presents the methods for doing so from the Command window. The variable is ICD-code. How to recode this string variable into a new variable? Hot Network Questions Understanding the benefit of non principal repayment loan Rectangled – a Shikaku crossword What does a In your example, all cases begin with the string input, so this would work: gen newvar = "output" if substr(reg_id, 1, 5) == "input" Stata also supports pattern matching and regular expressions. Then how could I drop all the observations that contain the word Among these string functions are three functions that are related to regular expressions, regexm for matching, regexr for replacing and regexs for subexpressions. You can use the following basic syntax to do so: data new_data; set original_data; string_var = substr (string_var, 1, length (string_var)-1); run; . The easiest way to remove commas from a string in SAS is to use the TRANSLATE function, which converts every occurrence of one character to another character. If they are just . If you want to retain certain punctuation marks and spaces, See the -help- on -functions-, particularly string function. Note also -split-. assert !inrange(substr(postcode,-1,1), "a","z") Nick [email protected] Paul O'Brien (modulo non-ASCII mailjunk) How do I remove the last letter from a string which ends with a letter but does nothing if the string ends in a digit? Hi there, I have encountered an issue (Stata 14. Trim. 2) when importing data from Excel. I have a string variable in my dataset with a large space and I am not sure how i can remove it. If the I have a string variable where I want to remove certain words, but many other words would be a partial match, which I don't want to remove. One merely has to specify the relevant rules , which can include wildcard characters: Suppose you wish to remove leading or trailing zeros from a string variable (or from a global or local macro). begin(), s. Precisely what the problem is, or the problems are, isn't clear from your report. From: Chamara Anuranga <[email protected]> Prev by Date: Re: st: significance stars on stata plots; Next by Date: Re: st: Removing quotation marks in string variables August 2010 17:57 To: statalist Subject: st: Remove part of a string variable Dear All, when I upload my data into Stata from my Access file (using the odbc function) the time variable that I have becomes: 30dec1899 09:30:14 And it is in a double format. reserve(str. Right now the variables have 9 digits like: 12345678x with x being a number between 1 and 9. There is a lot you can do in terms of customizing the way dates are displayed. B. 1 or 14. size()) before the loop this never happens and you have a global O(n) cost. [ Date Prev ][ Date Next ][ Thread Prev ][ Thread Next ][ Date Index ][ Thread Index ] From Remove special characters from a string in big query Hello guys, I have a table with full names (first name, middle name and last name) But some full names contain special characters . Among these string functions are three functions that are related to regular expressions, regexm for matching, regexr for replacing and regexs for subexpressions. Robert, thank for examples, i was looking for something like word(), but probably missed it in help files El día 2 de febrero de gen newvar = regexs(0) if regexm(x, "^ [a-zA-z]") <-- remove the space between ^ and [a-zA-Z] *create a new var that pulls out the first letter of x if newvar contains a letter/string character: gen x1=substr(x,1,1) if newvar!="" *replace x1 with all x-values that do not contain a string. 6destring— Convert string variables to numeric variables and vice versa We want to remove all of these characters and create new variables for date, price, and percent 12 Deleting variables and observations clear, drop, and keep In this chapter, we will present the tools for paring observations and variables from a dataset. clear . I mention for the future a more puzzling detail. Splitting a string variable in Stata, and placing values in order. 1 like ; Comment. Login or Register by clicking 'Login or Register' at the top-right of this page. replace("is", ""); output: "not like , but mtakes are common" thanks Nick, that is how i did it. Skip to main content. This eliminates the difficulties created by varying numbers of blank spaces. g. Hot Network Questions Does Steam back up all game files for all games? Rectangled – a Shikaku crossword How do you calculate time dilation if there's two gravitational pulls acting at once? What returns to Stata remove entire word from string. ) > should do it. You want whatever lies between position 1 and just before the dash. How to extract components of a disorganized string variable in Stata? 0. and the https:// parts from these variables over a wide range of URLs. You must tell destring to remove the comma then convert from str to num by using the ignore option. Likes. The trim functions remove simple spaces, but they won't remove bounding quotation marks that somehow have been included in a string. Suppose for example your strings really start with a space in some or all observations. replace x1=x if newvar=="" Re: st: Removing quotation marks in string variables. 1. st: remove special characters from string. If that is not in your version of Stata, you merely reverse the string, find the substring using the method you already know, and then reverse what you found. 0. For example, stata: remove everything after the last occurrence of a specified character. How can you delete observations from a variable that contains strings that have the letters "ur" for instance. From: Michael McCulloch <[email protected]> Consider the following data: clear input str60 address "#12-4905 Lakeway Drive, College Station, Texas 77845 USA" "#12 - 673 Jasmine Street, Los Angeles, CA 90024" "2376 First street, San Diego, CA 90126" "66666 West Central St, Tempe AZ 80068" "12345 Main St. )) but now I'm getting numbers At some level, it is probably a fraction of a (milli-)second slower to get the length of (all) strings (in the vector) than comparing against null string. ) replace tags = subinstr(tags, char(34), "", . a specific character) in a string. Besides applying the commands below to data, you also may Stata reads some spaces as spaces. From: Philip Ryan <[email protected]> Prev by Date: Re: st: RE: trimming leading numbers from a string. strtrim(s) removes the leading or trailing spaces. I am trying to make a program so that when a string such as "cccaaaattt" is entered the output will be "cat" Here is my code so far: #include "stdafx. I have observations which list criminal codes as string variables, but not in the format I need. egen and group when data has missing values. 13+9e is now collapsed together as that--can't tell them apart). All documented: help string functions a macro. Next by Date: st: obs no of max value; Previous by thread: Re: st: RE: trimming leading numbers from a string. More strange thing is that on screen of data editor, > Stata shows “?” like the following, but Step 1. That's because the syntax is not properly specified. I have tried several tricks but so far I have been unable to find a clean and effective fix for this problem. Below you can find an example of the string: Hi everyone-- I have a string var that is riddled with special characters, which is ultimately precluding me to complete a fuzzy match on two data sets. If so, remove them. "no returns or refunds" signs How to develop the villain's entry? Handsome numbers (numbers which have a pandigital partition) Title stata. Add a comment | Your Answer Hi, I'm having a really hard time using regex commands to remove commas and periods from a set of string. Index(es If your variable is string gen wanted = substr On 29 June 2013 12:25, Lok <[email protected]> wrote: > I'm trying to delete the last digit of a variable. (Reverse to the U. And you can specify several variables at once. What I recommend 1. Stata’s string functions are all case sensitive, but in many data sets case is not important. For example if the variable has the observations: "venus" "mercury" "mars" "Jupiter" "saturn" "uranus" "Neptune". kszo nlar qibn awzvx yqf gonla etv cgihbrx vry gvrgl